Find solution : $\large\frac{dy}{dx}$$= 1+ \sqrt {y-x+3}$

Question

$(a)\;2 \sqrt {y-x+3}=x+c \\ (b)\;y-x+3=\sqrt x +c \\ (c)\;\sqrt {y-x+3}=x+c \\ (d)\;y-x+3=\sqrt y+c$