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>>
JEEMAIN and NEET
>>
Mathematics
>>
Class12
>>
Differential Equations
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Q)
Solve :
y
′
+
tan
x
.
y
=
tan
x
y
(
π
4
)
=
1
(
a
)
y
=
e
sec
2
x
tan
2
x
2
+
c
(
b
)
y
=
e
tan
2
x
/
2
+
c
(
c
)
y
=
e
sec
2
x
tan
2
x
4
+
c
(
d
)
y
=
e
−
sec
2
x
tan
2
x
2
+
c
Share
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