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Solve : $y''+e^{2y}(y')^3=0$

$(a)\;y=e^{2x}+c_1 x+c_2 \\ (b)\;x= e^{2y}+c_1y+c_2 \\ (c)\;y=\frac{1}{4}.e^{2x}+c_1x +c_2 \\ (d)\;x=\frac{1}{4} e^{2y}+c_1y +c_2 $

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