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JEEMAIN and NEET
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Physics
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Class12
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Electrostatic Potential and Capacitance
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Initially the spheres A and B are at potential $\;V_{A}\;$ and $\;V_{B}\;$ respectively . Now sphere B is earthed by closing the switch . The potential of A will now become
$(a)\;0\qquad(b)\;V_{A}\qquad(c)\;V_{A}-V_{B}\qquad(d)\;V_{B}$
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