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Questions  >>  JEEMAIN and NEET  >>  Physics  >>  Class12  >>  Current Electricity
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A wire of resistance $10\Omega$ is bent to form a circle. $P$ and $Q$ are two points on it such that the arc $PQ$ subtends a right angle at the center. A $3V$ battery having internal resistance of $ 1\Omega$ is connected across $P$ and Q, the currents in the two parts of the circle are

$\begin {array} {1 1} (A)\;\large\frac{5}{26}A\: and \: \large\frac{15}{26}A & \quad (B)\;\large\frac{4}{25}A\: and \: \large\frac{12}{25}A \\ (C)\;\large\frac{3}{35}A\: and \: \large\frac{9}{25}A & \quad (D)\;\large\frac{6}{23}A\: and \: \large\frac{18}{23}A \end {array}$

 

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