$\begin{array}{1 1}(a)\;\large\frac{x\sec\theta}{a^2}+\frac{y\tan \theta}{b}\normalsize =1\\(b)\;\large\frac{x\sec\theta}{a}-\frac{y\tan \theta}{b}\normalsize =1\\(c)\;\large\frac{x\tan\theta}{a^2}+\frac{y\sec \theta}{b}\normalsize =1\\(d)\;\text{None of these}\end{array}$