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Questions  >>  JEEMAIN and NEET  >>  Physics  >>  Class12  >>  Wave Optics
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In a YDSE with $D= 1m,d=1mm$ light of wave length $500 \;nm$ is incident at an angle of $0.57^{\circ}$ with respect to axis of symmetry of experimental set up. If centre of symmetry of screen is 0. Then the intensity at point 0 in terms of intensity of central maxima $I_0$ is

$(a)\;2\;I_0 \\ (b)\;3\;I_0 \\ (c)\;I_0 \\ (d)\;None $

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