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An inductor of inductance $ L = 400\: mH$ and resistors of resistances $R1 = 2\Omega$ and $R2 = 2\Omega$ are connected to a battery of $emf\: 12V$ as shown in the figure. The internal resistance of the battery is negligible. The switch $K$ is closed at $t= 0$. The potential drop across $L$ as a function of time is

 

$\begin {array} {1 1} (A)\;6e^{-5t}V & \quad (B)\;\bigg( \large\frac{12}{t} \bigg) e^{-3t}V \\ (C)\;6 \bigg(1-e^{\large\frac{-t}{0.2}} \bigg)V & \quad (D)\;12e^{-5t}V \end {array}$

 

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