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Questions  >>  JEEMAIN and NEET  >>  Chemistry  >>  Solutions
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At room temperature $25^{\large\circ}C$,the expression for total pressure of mixture of methanol and ethanol solution is given by P(in torr)$=135+120X$ where $X$ is mol fraction of methanol,Hence

$\begin{array}{1 1}(a)\;\text{vapour pressure of pure ethanol in 135 torr}\\(b)\;\text{vapour pressure of pure ethanol in 255 torr}\\(c)\;\text{both (a) and (b) correct}\\(d)\;\text{mixture is completely immiscible}\end{array}$

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