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Questions  >>  JEEMAIN and NEET  >>  Physics  >>  Class12  >>  Current Electricity
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Two sources of equal emf are connected to an external resistance R. The internal resistance of the two sources are R1andR2(R2>R1). If the potential difference across the source having internal resistance R2 is zero then,

(A)R=R2×(R1+R2)/R2R1)(B)R=R2R1(C)R=R1R2/(R1+R2)(D)R=R1R2/(R2R1)

 

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