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JEEMAIN and NEET
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Physics
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Class12
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Current Electricity
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Q)
Time taken by a $836\: W$ heater to heat one liter of water from $10^{\circ}C\: to\: 40^{\circ}C$ is
$\begin {array} {1 1} (A)\;50s & \quad (B)\;100s \\ (C)\;150s & \quad (D)\;200s \end {array}$
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