Three wires of the same material are connected in parallel to a source of emf. Their lengths are in the ratio 1 : 2 : 3 and cross-sectional areas are in the ratio 2 : 4 : 1. Then, the ratio of power dissipated across them will be

Question

$\begin {array} {1 1} (A)\; 6 : 6 : 1 & \quad (B)\;2 : 8 : 3 \\ (C)\;4 : 32 : 3 & \quad (D)\;2 : 8 : 9 \end {array}$