The EMF of cell $Ag/AgCl(K_{sp})(saturated\; sol)\parallel Cl^-(C_1)/AgCl(K_{sp}/Ag)$ is given by

Question

$\begin{array}{1 1}(a)\;E=-\large\frac{0.059}{1}\normalsize\log \large\frac{\sqrt{K_{sp}}}{C_1}\\(b)\;E=-\large\frac{0.059}{1}\normalsize\log \large\frac{C_1}{\sqrt{K_{sp}}}\\(c)\;E=-\large\frac{0.059}{1}\normalsize\log \large\frac{\sqrt{K_{sp}}}{C_1^2}\\(d)\;E=\large\frac{0.059}{1}\normalsize\log \large\frac{C_1}{\sqrt{K_{sp}}}\end{array}$