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JEEMAIN and NEET
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Chemistry
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Electrochemistry
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Consider the relation,$2Ag^++Cd\rightarrow 2Ag+Cd^{+2}$ the standard electrode potentials for $Ag^+/Ag$ and $Cd^{+2}/Cd$ couples $0.8\;V$ and $0.04\;V$ respectively Then the emf of given reaction will be (if $[Cd^{+2}]=0.1M,[Ad^+]=1M)$
$\begin{array}{1 1}(a)\;0.33V&(b)\;0.43V\\(c)\;0.23V&(d)\;0.53V\end{array}$
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