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A mass m is to be placed on the rod of length L and pivoted at its centre at a distance x from the left end of the rod so that the system shown in figure remains in equilibrium . Find x (Ignore the force between Q (beaneth q ) and 2q and the force between Q (beneath 2q) and q .

$(a)\;\large\frac{L}{2}\;(1-\large\frac{k\;q\;Q}{m\;g\;h^2})\qquad(b)\;\large\frac{L}{2}\;(1+\large\frac{k\;q\;Q}{m\;g\;h^2})\qquad(c)\;L\;(1-\large\frac{k\;q\;Q}{m\;g\;h^2})\qquad(d)\;\large\frac{L}{2}\;(1+\large\frac{k\;q\;Q}{2 m\;g\;h^2})$

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