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Calculate the minimum weight of NaOH required to be added in R.H.S to consume all the $H^+$ present in R.H.S of cell of emf to .701V at $25^{\large\circ}C$.Given: $Zn/Zn^{+2}(0.1M)\parallel HCl$(1litre)$/H_2/$(1atm)/P:-$E^0_{Zn/Zn^{+2}}=0.7602$

$\begin{array}{1 1}(a)\;2.3gm\\(b)\;1.92gm\\(c)\;1.26gm\\(d)\;3.26gm\end{array}$

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