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A solid metallic sphere of radius a is surrounded by a conducting spherical shell of radius b $\;(b >a)\;$ . The solid sphere is given a charge Q . Potential at the surface of the solid sphere is $\;V_{a}\;$ and at the surface of spherical shell is $\;V_{b}\;$. If we put -4Q charge on the shell the potential difference between the sphere and shell becomes $\;( \bigtriangleup V )\;.$ Now we earthed the outer shell and the charge on the ouer shell is $\;q_{1}\;$.Now we removed the earthing connection from the shell and earthed the inner solid sphere. Charge on solid sphere becomes $\;q_{2}\;$. Answer the following question based on the passage. Potential difference $\;(\bigtriangleup V) \;$ measured between the inner solid sphere and outer shell after putting a charge -4Q is

$(a)\;V_{a}-3V_{b}\qquad(b)\;3(V_{a}-V_{b})\qquad(c)\;V_{a}\qquad(d)\;V_{a}-V_{b}$

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