$\begin{array}{1 1}(a)\;\text{DBAH stands for deutrium -t-butoxyaluminium-hydride}\\(b)\;\text{The reduction of }Ph-CH-CH-CO-CH_3\text{ Li in }NH_3\text{ in either solvent gives }Ph-CH=CH-CH(OH)CH_3\\(c)\;\text{LABH stands for }Li(OCMe_3)_3AlH\\(d)\;\text{None of these}\end{array}$
