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Questions  >>  JEEMAIN and NEET  >>  Physics  >>  Class12  >>  Atoms
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Light quanta with an energy 4.9 eV ejects photoelectrons from a metal with work function 4.5 eV .Then the maximum impulse transimitted to surface of metal when each electron flies out. Then de-Broglie wavelength of photoelctrons :

$(a)\;2 \times10^{-6} m\qquad(b)\;2 \times10^{-8} m\qquad(c)\;2 \times10^{-9} m\qquad(d)\;2 \times10^{-10} m$

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