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Questions  >>  CBSE XI  >>  Math  >>  Sequences and Series
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Find the sum to $n$ terms of the sequence $8,88,888,.............$

$\begin{array}{1 1}\large\frac{8}{9}[\large\frac{10}{9}(10^n-1)] \\\large\frac{8}{9}[\large\frac{10}{9}(10^n-1)-1] \\ \large\frac{8}{9}[\large\frac{10}{9}(10^n-1)-n] \\ \large\frac{8}{9}[\large\frac{10}{9}10^n-1-n] \end{array} $

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