$\begin{array}{1 1}\large\frac{8}{9}[\large\frac{10}{9}(10^n-1)] \\\large\frac{8}{9}[\large\frac{10}{9}(10^n-1)-1] \\ \large\frac{8}{9}[\large\frac{10}{9}(10^n-1)-n] \\ \large\frac{8}{9}[\large\frac{10}{9}10^n-1-n] \end{array} $