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JEEMAIN and NEET
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Chemistry
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Chemical Thermodynamics
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Q)
H
2
O
(
g
)
+
C
(
s
)
→
C
O
(
g
)
+
H
2
(
g
)
;
Δ
H
=
131
kJ.
C
O
(
g
)
+
1
2
O
2
(
g
)
→
C
O
2
(
g
)
;
Δ
H
=
−
282
kJ.
H
2
(
g
)
+
1
2
O
2
(
g
)
→
H
2
O
(
g
)
;
Δ
H
=
−
242
kJ.
C
(
s
)
+
O
2
(
g
)
→
C
O
2
(
g
)
;
Δ
H
=
X
kJ. Based on the above thermochemical equations find the value of X.
(a) +393 kJ
(b) -655 kJ
(c) -393 kJ
(d) +655 kJ
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