$ \begin{array}{1 1}(a)\;\text{Pyrrole is more basic because its non binding }e^{\ominus}\text{ occupy }SP^3\text{ orbital}\\(b)\;\text{Pyridine is more basic because its non binding }e^{\ominus}\text{ is not part of aromatic sextet}\\(c)\;\text{Both are equally basic}\\(d)\;\text{Pyridine is less basic because it is }3^0\text{ amine}\end{array}$
