(A)17log|x−2||x+2|−√37tan−1(x√3)+c(B)17log|x−2||x+2|+√37tan−1(x√3)+c(C)17log|x−2||x+2|+3√7tan−1(x√3)+c(D)17log|x−2||x+2|−3√7tan−1(x√3)+c