$\begin{array}{1 1}\large\frac{n(n+1)(3n^2+5n+1)}{3} \\ \large\frac{n(n+1)(3n^2+5n+1)}{6} \\\large\frac{n(n+1)(3n^2+5n-1)}{6} \\ \large\frac{n(n+1)(3n^2+5n-1)}{3} \end{array} $