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Q)

For an ideal gas, the following conversions are made:

1)P,V,T(initial conditions)Isothermally2V,Pi,T

2)P,V,T(initial conditions)Adiabatically2Vi,Pa,T

Now, if Kgas=PaPi, find KH2KHe (A) 1 (B) 1.2 (C) 0.83 (D) 1.44
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