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Q)

$4FeCl_3+3K_4Fe(CN)_6 \longrightarrow (x)+12KCl$ the x formed :

$(a)\;Fe_4(Fe(CN)_36]_3 \\(b)\;Fe(Fe(CN)_6]_3\\(c)\; Fe(Fe(CN)_3]_6 \\(d)\;Fe(Fe(CN)_2]_6 $

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