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Questions  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Thermodynamics
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100 g of ice at $\;0^{0}C\;$ is mixed with 100 g of water at $\;20^{0}C\;$ . Latent heat of fusion of fusion is 80 cal/g & specific heat of water is $\;1 cal /g^{0}C\;$ . The final temperature of mixture =

$(a)\;20^{0}C\qquad(b)\;10^{0}C\qquad(c)\;5^{0}C\qquad(d)\;0^{0}C$

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