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Questions  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Thermodynamics
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For a gaseous reaction 2A2(g)+5B2(g)2A2B5(g) at 27C the heat change at constant pressure is found to be 50160J. Calculate the value of internal energy change (ΔU).(R=8.314J/Kmol)

(a)37689J(b)37689J(c)62631J(d)62631J

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