Email
Chat with tutors
Login
Ask Questions, Get Answers
Menu
X
home
ask
tuition
questions
practice
papers
mobile
tutors
pricing
X
Questions
>>
JEEMAIN and NEET
>>
Physics
>>
Class11
>>
Thermodynamics
Next similar question
Answer
Comment
Share
Q)
For a gaseous reaction
2
A
2
(
g
)
+
5
B
2
(
g
)
→
2
A
2
B
5
(
g
)
at
27
∘
C
the heat change at constant pressure is found to be
−
50160
J
. Calculate the value of internal energy change
(
Δ
U
)
.
(
R
=
8.314
J
/
K
m
o
l
)
(
a
)
37689
J
(
b
)
−
37689
J
(
c
)
62631
J
(
d
)
−
62631
J
Share
Please
log in
or
register
to add a comment.
Please
log in
or
register
to answer this question.
Found
1
answer. Click to login & view.
Next Similar Question >
Home
Ask
Tuition
Questions
Practice
Your payment for
is successful.
Continue
...
Please Wait