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Questions  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Thermodynamics
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Estimate the value of $ \Delta S^{\circ}_{298}$ for the dissociation of calcium carbonate given that, $ \Delta H^{\circ}_{298}$ for the reaction is $178\: kJ$. The equilibrium pressure is one bar at $897^{\circ}C.(R = 8.314\: J/Kmol)$

$\begin {array} {1 1} (A)\;132.66\: J/K & \quad (B)\;-152.15 \: J/K \\ (C)\;-132.66\: J/K & \quad (D)\;152.15 \: J/K \end {array}$

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