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CBSE XII
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Math
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Differential Equations
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General solution of $\frac{dy}{dx} + y\tan x = \sec x$ is
\[(A)\;y\sec x=\tan x+c \quad (B)\;y\tan x=\sec x+c\quad(C)\;\tan x=y\tan x+c \quad(D)\;x\sec x=\tan y+c\]
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