The general solution of $\frac{dy}{dx}-y=\sin x$ is

Question

$\begin{array}{1 1} y=2[\sin x+cos x]+ce^{-x} \\ y= \frac{1}{2} [\sin x +\cos x ]+ce^{-x} \\ y=\frac{-1}{2} [\sin x+\cos x]+ce^{-x} \\ y=\frac{1}{2} [\sin x+\cos x]+ce^{-x} \end{array}$