Find the equation of the tangent at the point $(0,2)$ to the circle $x^2+y^2-4x+2y-8 = 0$

Question

$\begin{array}{1 1} (A) y = \large\frac{2}{3} x- 2 \\ (B) y = \large\frac{3}{2} x+ 2 \\ (C) y = \large\frac{2}{3} x+ 2 \\ (D) y = \large\frac{1}{3} x-2 \end{array} $