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Questions  >>  JEEMAIN and NEET  >>  Physics  >>  Class12  >>  Alternating Current
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An AC Source gives a voltage of $V= 20\; \cos \;(2000 \;t)$. It is connected in a circuit as shown. The voltmeter reading is

$(a)\;4\;V \\ (b)\;4 \sqrt 2\;V \\(c)\;2 \sqrt {3} \\(d)\;3\sqrt {2} V$

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