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JEEMAIN and NEET
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Physics
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Class12
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Alternating Current
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The equation of AC voltage is $E=220\; \sin (wt+\large\frac{\pi}{6})$ and AC current is $I= 10 \sin (wt+\large\frac{\pi}{6})$ The average power dissipated is
$(a)\;150\;W \\ (b)\;550\;W \\(c)\;250\;W \\(d)\;50\;W $
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