In alkaline medium,$KMnO_4$ reacts as follows:$2KMnO_4+2KOH\rightarrow 2K_2MnO_4+H_2O+O$.Therefore,the equivalent weight of $KMnO_4$,will be

Question

$\begin{array}{1 1}(a)\;31.6&(b)\;52.7 \\(c)\;7.0&(d)\;158.0\end{array}$