Email
Chat with tutors
Login
Ask Questions, Get Answers
Menu
X
home
ask
tuition
questions
practice
papers
mobile
tutors
pricing
X
Questions
>>
JEEMAIN and NEET
>>
Chemistry
>>
Solutions
Next similar question
Answer
Comment
Share
Q)
The vapour pressure of pure liquid solvent A is 0.80atm.When a non volatile substance B is added to the solvent,its vapour pressure drops to 0.40atm,the mole fraction of component B in the solution is
(
a
)
0.25
(
b
)
0.75
(
c
)
0.50
(
d
)
0.40
Share
Please
log in
or
register
to add a comment.
Please
log in
or
register
to answer this question.
Found
1
answer. Click to login & view.
Next Similar Question >
Home
Ask
Tuition
Questions
Practice
Your payment for
is successful.
Continue
...
Please Wait