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Questions  >>  JEEMAIN and NEET  >>  Chemistry  >>  Solutions
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Q)

The vapour pressure of pure liquid solvent A is 0.80atm.When a non volatile substance B is added to the solvent,its vapour pressure drops to 0.40atm,the mole fraction of component B in the solution is

(a)0.25(b)0.75(c)0.50(d)0.40

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