If $A = \begin{bmatrix} 1 & -1 & 1 \\ 2 & 1 & -3 \\ 1 & 1 & 1 \end{bmatrix}$, find $A^{-1}$ and hence solve the equation : $x+2y+z=4, -x+y+z=0 ,x-3y+z = 2$

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