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JEEMAIN and NEET
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Chemistry
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Hydrogen
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2
K
3
F
e
(
C
N
)
6
+
2
K
O
H
→
x
+
y
+
z
,
H
2
O
2
+
z
→
y
+
w
.The
y
is
(
a
)
H
2
(
b
)
2
H
2
O
(
c
)
H
2
O
(
d
)
2
H
O
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