Find the sum of $n$ terms of the series whose $n^{th}$ term is $(2n-1)^2$

Question

$\begin{array}{1 1}\large\frac{n(4n^2-5)}{3} \\\large\frac{n(4n^2+1)}{3} \\\large\frac{n(4n^2-1)}{3} \\\large\frac{n(4n^2-n-1)}{3} \end{array}$