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Questions  >>  CBSE XI  >>  Math  >>  Conic Sections
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Find the equation of the parabola that satisfies the given conditions: Vertex $(0,0)$ and Focus $(3,0)$

$\begin{array}{1 1} y^2=12 x \\ x^2=-12y \\ y^2=-12x \\ x^2=12y \end{array} $

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