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Questions  >>  CBSE XI  >>  Math  >>  Conic Sections
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Find the equation of a parabola that satisfies the following condition - vertex $(0,0)$ and passing through $(5,2)$ and symmetric with respect to y-axis.

$\begin{array}{1 1} x^2= \frac{25}{2} y \\y^2= \frac{25}{8} x \\x^2= \frac{-25}{4} y \\ y^2= \frac{-25}{16} x \end{array} $

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