Find the equation of an ellipse that satisfies the following conditions: Vertices $\;(\pm6,0)$, Foci $\;(\pm4,0)$

Question

$\begin{array}{1 1} \frac{x^2}{36}+\frac{y^2}{20}=1 \\ \frac{x^2}{9}+\frac{y^2}{20}=1 \\ \frac{x^2}{36}+\frac{y^2}{16}=1 \\ \frac{x^2}{16}+\frac{y^2}{36}=1\end{array}$