$\begin{array}{1 1} \large\frac{n}{3}\big[n^2+3n+5\big] \\ \large\frac{n}{3}\big[n^2-3n+5\big] \\ \large\frac{n}{3}\big[n^2+3n-5\big] \\ \large\frac{n}{3}\big[n^2+4n+5\big]\end{array} $
