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If the lines $2x+3y+1=0,\qquad 3x-y-4=0$ lie along diameter of a circle of circumference $10\pi$ then the equation of the circle is :

$\begin{array}{1 1}(A)\;x^2+y^2+2x-2y-23=0\\(B)\;x^2+y^2-2x-2y-23=0 \\(C)\;x^2+y^2+2x+2y-23=0 \\(D)\;x^2+y^2-2x+2y-23=0 \end{array}$

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