If $\omega=\large\frac{z-\perp}{z+1}$$\quad (z\neq -\perp)$ and $\mid z\mid =\perp$ then $Re(\omega)$ equals

Question

$\begin{array}{1 1} \frac{\sqrt 2 }{|z+1|^2 } \\ \bigg|\frac{z}{z+1} \bigg| \frac{1}{|z+1|^2} \\ zero \\ None\;of\;these \end{array}$