If $z$ is a complex number having least absolute value and $|z-2+2i|=1$ then $z=$

Question

$\begin{array}{1 1}(A)\;(2-\large\frac{1}{\sqrt 2})\normalsize (1-i)\\(B)\;(2-\large\frac{1}{\sqrt 2})\normalsize (1+i)\\(C)\;(2+\large\frac{1}{\sqrt 2})\normalsize (1-i)\\(D)\;(2+\large\frac{1}{\sqrt 2})\normalsize (1+i)\end{array}$