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The minimum area of triangle formed by the tangents to the ellipse $\large\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$ coordinate axes is :

$\begin{array}{1 1}(A)\;ab\;sq.units \\(B)\;\frac{(a+b)^2}{2} \;sq.units \\(C)\;\frac{a^2+b^2}{2}\;sq.units \\(D)\;\frac{a^2+ab+b^2}{3} \end{array}$

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