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If one root of $(a^2-5a+3)x^2+(3a-1)x+2=0$ is double the other,then the value of a is :

$\begin{array}{1 1}(A)\;\large\frac{2}{3}&(B)\;\large\frac{1}{3}\\(C)\;\large\frac{-1}{3}&(D)\;\large\frac{-2}{3}\end{array} $

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