$f(x)=\Large\frac{x^2-1}{x^2+1}$ for every real number then minimum value of $$\begin{array}{1 1}(a)\;does\; not\; exist & \qquad(b)\;is\;not\;attained\;even\;though\;f\;is\;bounded\\(c)\;is\;equal\;to\;1 & \qquad(d)\;is\;equal\;to\;-1\end{array}$$

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