Q)
The tangent to the curve\[x=a\sqrt{\cos 2\theta} \cos\theta y=a\sqrt{cos2\theta}\sin \theta\]at the point corresponding to $ \theta =\frac{\pi}{6}$ is \begin{array}{1 1}(a)\;Parallel\; to\; the\; x-axis & \qquad (b)\;Parallel\; to\; the\; y-axis \\ (c)\;Parallel\; to\; the\; line\; y = x & \qquad(d)\;none\;of\;these\end{array}
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